The magnetic field of an electromagnetic wave is given by : -
$$\vec{B} =1.6 \times10^{-6} \cos\left(2\times10^{7} z +6 \times10^{15}t\right)\left(2\hat{i} +\hat{j}\right) \frac{Wb}{m^{2}} $$
The associated electric field will be :-

1) $$\vec{E} =4.8 \times10^{2} \cos\left(2\times10^{7}z + 6\times10^{15}t\right)\left(\hat{i} -2\hat{j}\right) \frac{V}{m} $$
2) $$\vec{E} =4.8 \times10^{2} \cos\left(2\times10^{7}z - 6\times10^{15}t\right)\left(2\hat{i} + \hat{j}\right) \frac{V}{m} $$
3) $$\vec{E} =4.8 \times10^{2} \cos\left(2\times10^{7}z - 6\times10^{15}t\right)\left( - 2\hat{i} + \hat{j}\right) \frac{V}{m} $$
4) $$\vec{E} =4.8 \times10^{2} \cos\left(2\times10^{7}z + 6\times10^{15}t\right)\left( -1 \hat{i} + 2\hat{j}\right) \frac{V}{m} $$