Solution:
SOLUTION
We know that, for a string, frequency is proportional to square root of Tension in the string.
i.e., f∝ √T
Let the tuning fork frequency be f and frequency of the string be f1? and f2? for the values of tension as 225N and 256N respectively.

As the tuning fork produces 6 beats per second on each of the case, we have f−f1? = 6 and f2? − f = 6
Using 16f1 ?= 15f2?, we have 15(f2?−f) + 16(f−f1?) = (16+15) × 6
⇒f = 31×6=186Hz