1 Coordination Compounds
One mole of the complex compound Co(NH3)5Cl3 gives three moles of ions on dissolution in water. One mole of the same complex reacts with two moles of AgNO3 solution to yield two moles of AgCl(s). The structure of complex is:
1) $$[Co(NH_{3})_{4}Cl]Cl_{2}.NH_{3}$$ 2) $$[Co(NH_{3})_{5}Cl]Cl_{2}$$ 3) $$[Co(NH_{3})_{3}Cl_{3}]2.NH_{3}$$ 4) $$[Co(NH_{3})_{4}Cl_{2}]Cl.NH_{3}$$
$$Co(NH_{3})_{5}Cl_{3}$$ gives three ions- one complex ion and two chloride ion. Which is confirmed by reaction with silver nitrate. $$2AgNO_3+2Cl^-\rightarrow 2AgCl$$ So, compound is $$[Co(NH_{3})_{5}Cl]Cl_{2}$$.
2 Purification and Characterisation of Organic Compounds
The fragrance of the flower is due to the presence of some steam volatile organic compounds called essential oils. These are generally insoluble in water at room temperature but are miscible with water vapour in the vapour phase. A suitable method for the extraction of these oil from the flower is:
1) distillation with reduced pressure
2) distillation
3) steam distillation
4) chromatography
SOLUTION
As the component is miscible with water vapour in vapour phase so steam distillation will be most suitable method for extraction.
3 Aldehydes Ketones and Carboxylic Acids
Acetone is soluable in water due to 1. methyl group 2. neutral nature 3. dissociation in water 4. hydrogen bonding
4 Ionic Equilibrium
The value of observed and calculate molecular weights of silver nitrate are 92.64 and 170 respectively. The degree of dissociation of silver nitrate will be :
1) 60% 2) 83.5% 3) 85.3% 4) 41.6%
i for AgNO3 = observed mol wt / normal mol.wt?
=1+α
α=i−1%
=17092.64−1
=0.835=83.5%
5 Classification of Elements and Periodicity
The long form of the periodic table has _______ periods, and _______vertical columns.
1) 6;8 2) 6;18 3) 8;12 4) 7;18
6 Surface Chemistry
Calculate the surface area in (sq m) of a catalyst that adsorbs 103cm3 of nitrogen reduced to STP per gram in order to form the monolayer. The effective area (in m2) occupied by N2? molecule on the surface is: ( surface area of N2?=1.62×10−15cm2)
1) 4115 m2 2) 2355 m2 3) 4355 m2 4) 435.5 m2
According to the given data,
Number of N2? molecules = Volume(ml) × NA / Volume at STP(in ml)
= (103×6.023×1023) / 22400 = 2.69×1022
Total area covered by N2? = 2.69×1022 × 1.62×10−15 = 435×105 cm2 = 4355 m2.
7 Basic Principles of Organic Chemistry
Tautomerismwill be exhibited by 1) (CH3)3CNO 2) (CH3)2NH 3) R3CNO2 4) RCH2NO2
only RCH2NO2 has α-hydrogen atoms - > will shows tautomerism
8 Hydrocarbons
Which of the following do not give glyoxal on ozonolysis followed by reaction with Zn and H2O?
1) Benzene 2) HC=CH 3) Toluene 4) Ethene
Benzene don't undergo ozonolysis under room temperature. It can occur only at very high temperature.
9 Ionic Equilibrium
At a particular temperature, the ratio of molar conductance to specific conductance of 0.01 M NaCl solution is:
1) 105 cm3mol−1 2) 103 cm3mol−1 3) 10 cm3mol−1 4) 105 cm2mol−1
∧m = (K×1000 )/ M
where,
∧m= Molar conductance
K= Specific conductance
⇒∧m / K
10 Environmental Chemistry
Silk and woolen clothes are often damaged by
1) Flies
2) Insects
3) Bacteria
4) Animals
Because insects have the ability to digest silk and wool. Examples of insects that damage the clothes are-silverfish, cockroach, moth etc.
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