SOLUTION

We know that for Geometrical Isomer we need a double bond between carbon atom  (this restricts rotation) and carbon atom at two sides must be linked to two different groups.

Solution

A mixture X containing 0.02 mol of [Co(NH3)5SO₄Br[ and 0.02 mol of [CO(NH3)5Br]SO₄ was prepared in 2L of solution of [Co(NH3)5SO4Br 0.01[Co(NH3)5SO4Br.
1L of mixture X+ excess AgNO₃→0.01molAgBr→0.01mol AgBr
1L of mixture X+ excess BaCl₂→0.01molBaSO₄
This is according to the following reactions taking place:
[Co(NH3)5Br]SO₄+AgNO₃→[Co(NH₃)5SO₄]NO₃+AgBr?↓
Co(NH₃)5Br]SO₄+BaCl₃→Co(NH₃)5Br]SO₄ +BaCl₃→ [Co(NH₃)5Br]Cl2+BaSO4?↓

 The hexagonal close packing and the face-centred cubic system

have the closest packing as their packing efficiency is 74% and

thus (3) represent the correct solution.

Solution: 

CaF₂ ?Ca²⁺ + 2F⁻

Ksp=[Ca²⁺][F−]²=S(S +0.1)² = S × 0.12 = 5.3×10⁻⁹

Note: S<<0.1so, S+0.1≈0.1

⇒S=5.3×10⁻⁷ M

Solution

Normality=molarity×basicity or acidity (for HCl)
N2=0.4 × 1=0.4N basicity=1 (for NaoH acidity=1)
N1=0.6 × 1=0.6N,V1=?,V2=30cm3
From the equation, N1V1=N2V2
0.6 × V1 = 0.4×30

$$\displaystyle{V}_{{{1}}}=\frac{{{0.4}\times{30}}}{{{0.6}}}={20}{c}{m}^{{{3}}}$$

SOLUTION

Three important oxidation states of phosporous are :
+3 is due to the participation of only 3P³(due to inert pair effect). Only three electrons involve in bond formation.
+5 is due to the participation of  3s²3P³(due to absence of  inert pair effect). All the five electrons involves in bond formation.
-3 is due to gain of three electrons as it has five electrons in valence shell so as to attain octet configaration.

SOLUTION

First, write the balanced chemical equation for the equilibrium.

C(s) +2N?O(g) ? CO?(g) + 2N?(g)

There was no CO? or N? present at the beginning.

The reaction produced CO? to a pressure of 0.030 atm. It also produced twice as much N? as CO?.

PN?=2PCO? = 2 × 0.030 atm = 0.060 atm

Solution: 

Dissociation in chemistry and biochemistry is a general process in which molecules (or ionic compounds such as salts, or complexes) separate or split into smaller particles such as atoms, ions or radicals, usually in a reversible manner. It may or may not form charged species as shown below. 

i). NaCl ? Na⁺ + Cl⁻

ii). N₂O₄ ?2NO₂