Solution:
Solution
The crystal field splitting energy of complexes is the difference in the energy of two sets of d-orbitals during the transition of electrons. The relationship between the crystal field splitting energy of octahedral and tetrahedral complexes is,
$$\Delta_t = \dfrac{4}{9}\Delta_o$$
where, $$\Delta_t=$$ crystal field splitting energy of tetrahedral complexes (in $$cm^{-1}$$)
$$\Delta_o=$$ crystal field splitting energy of octahedral complexes (in $$cm^{-1}$$)
Here $$[Ni(H_2O)_6]^{2+}$$ forms an octahedral complex having $$\Delta_o=8500 \ cm^{-1}$$ and $$[Ph_4As]_2[NiCl_4]$$ forms a tetrahedral complex. So, value of $$\Delta_t$$ for $$[Ph_4As]_2[NiCl_4]$$ is,
$$\Delta_t=\dfrac{4}{9}\times 8500=3778 \ cm^{-1}$$