Solution:
Solution
Given, Weight of benzoic acid = 1.89 g
Temperature of bomb calorimeter = 25?C
Mass of water (m) = 18.94 kg = 18940 g
Increse in temperature (ΔT) = 0.632oC
ans Specific heat of water (s) = 0.998 cal/g/deg
We know that heat gained by water or heat liberated by benzoic acid
(Q) = msΔT=18940×0.998×0.632=11946.14cal
Since, 1.89 g of acid liberates 11946.14 cal of heat,
∴ heat liberated by 122 g of acid (1 mol) = $$ \frac{11946.14\times 122}{1.89}$$ = 77126.5 cal = 771.12 kcal
(where 122 g is the molecular weight of benzoic acid)