NSEC CHEMISTRY

DAILY CHEMISTRY TEST QUESTIONS

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1 Aldehydes Ketones and Carboxylic Acids

Which of the following will form when calcium acetate is distilled?

1) Formaldehyde

2) Ethanal

3) Propanal

4) Acetone

Option 1

Option 2

Option 3 Solution:

Option 4

2 Ionic Equilibrium

What volume of decinormal K₂Cr₂O₇ solution would be needed to convert 1.19 g of tin to stannic chloride in an acidic medium? (ASn = 119ASn = 119)

1) 400 ml
2) 200 ml
3) 100 ml
4) 2800 ml

Option 1 Solution:

SOLUTION

No.of moles of tin in 1.19g of tin=1.19=1.19

n=0.01

as Sn is converting to SnCl₄ i.e. Sn⁰→Sn⁺⁴

Thus n_f= 4

Normality of Kr₂Cr₂O₇ = O.1N

∴0.1N×V=0.01×4

V=0.42=400ml

400ml of volume of decinormal Kr₂Cr₂O₇solution would be needed

Option 2

Option 3

Option 4

3 Solid State

An element having bcc geometry has atomic mass 50. Calculate the density of the unit cell, if its edge length is 290 pm

1) 68.1g/cm³
2) 5.81g/cm³
3) 6.81g/cm³
4) none

Option 1

Option 2

Option 3 Solution:

Solution

$$density = \frac{Z\times M}{a^{3}\times N_{A}}$$

$$density = \frac{2\times 50}{(290\times 10^{-10})^{3}\times 6.022\times 10^{23}}$$

$$=6.81 g/cm^3$$

Option 4

4 Aldehydes Ketones and Carboxylic Acids

The final product formed when acetaldehyde is reduced with sodium and alcohol is

1) Ethane
2) Ethyl alcohol
3) Ethylene
4) All

Option 1

Option 2 Solution:

Solution

CH₃CHO + 2[H] → CH₃-CH₂OH [ in presence of Na/ Alcohol]

Option 3

Option 4

5 Purification and Characterisation of Organic Compounds

The process of separation of an organic compound from its aqueous solution by shaking with a suitable solvent is termed solvent extraction or differential extraction.
The organic compound present in aqueous layer moves to the organic solvent because:

1) the organic substance is more soluble in the organic solvent

2) organic compound being lighter moves in the upper layer

3) organic solvent is insoluble in water hence organic compound moves up

4) from the supersaturated aqueous solution the solute starts diffusing

Option 1 Solution:

SOLUTION

As the organic solvent is immiscible with aqueous solvent and organic compounds are more soluble in organic solvent so it will distribute more in organic phase than aqueous phase.

Option 2

Option 3

Option 4

6 S � Block Elements

Which of the following is not an ingredient of clinker cement?

1) Calcium silicate
2) Aluminium silicate
3) Calcium aluminium silicate
4) Gypsum

Option 1

Option 2

Option 3

Option 4 Solution:

Solution

The four main components of clinker are:

Alite: approximately tricalcium silicate (typically about 65% of the total)
Belite: approximately dicalcium silicate (typically about 15% of the total)
Aluminate: very approximately tricalcium aluminate (typically about 7%of the total)
Ferrite: very approximately tetracalcium aluminoferrite (typically about 8% of the total)
Thus Gypsum is not an ingredient of clinker while it is added in the cement formation process after formation of clinker.

7 Thermodynamics

Two moles of an ideal gas initially at 27^oC and one atmospheric pressure are compressed isothermally and reversibly till the final pressure of the gas is 10 atm. Calculate q for the process.

1) 11488 J
2) – 11488 J
3) 11588 J
4) – 11688 J

Option 1

Option 2 Solution:

Solution

Here, n = 2 moles T = 27^oC = 300 K, P₁ = 1 atm, P₂ = 10 atm

w = –2.303 n RT log (P1 /P 2) = – 2.303 x 2 x 8.314 JK^–1mol^–1

300 K × log (1 / 10) = 11488 J

For isothermal compression of ideal gas, ΔU = 0

Further, ΔU = q + w

∴ q = – w = – 11488 J.

Option 3

Option 4

8 Ionic Equilibrium

The compound whose 0.1 M solution is basic is

1) Sodium acetate

2) Ammonium sulphate

3) Ammonium chloride

4) Ammonium acetate

Option 1 Solution:

Solution

CH3COONa is a salt of weak acid, (CH3COOH) and strong base (NaOH).

Option 2

Option 3

Option 4

9 States of Matter

Some moles of O₂ diffuse through a small opening in 18 second. Same number of moles of an unknown gas diffuse through the same opening in 4545 second. Molecular mass of the unknown gas is:

1) $$32\times \dfrac {(45)^{2}}{(18)^{2}}$$
2) $$32\times \dfrac {(18)^{2}}{(45)^{2}}$$
3) $$(32)^{2}\times \dfrac {45}{18}$$
4) $$(32)^{2}\times \dfrac {18}{45}$$

Option 1 Solution:

Solution

The rate of diffusion is the ratio of number of moles diffuesd to the time taken for diffusion

The rate of diffusion is inversely proportional to the square root of its molar mass.
$$\displaystyle \dfrac {r_{O2}}{r_X}= \dfrac {n_{O2}}{t_{O2}} \times \dfrac {t_{X}}{n_X} =\sqrt {\dfrac {M_X}{M_{O2}}}$$
$$\displaystyle n_{O2}=n_X$$
$$\displaystyle    \dfrac {n_{X}}{ 18} \times \dfrac {45}{n_X} =\sqrt {\dfrac {M_X}{32}}$$

$$\displaystyle   \dfrac {45}{ 18} =\sqrt {\dfrac {M_X}{32}}$$
$$\displaystyle    \dfrac {(45)^2}{ (18)^2}= \dfrac {M_X}{32}$$
The molecular mass of gas X is $$\displaystyle M_X = 32\times \dfrac {(45)^{2}}{(18)^{2}}$$ g/mol.

Option 2

Option 3

Option 4

10 Chemical Bonding and Molecular Structure

Which bond angle around X would result in the maximum dipole moment for the triatomic molecule XY₂?

1) q = 120^o

2) q = 150^o

3) q = 90^o

4) q = 180^o

Option 1

Option 2

Option 3 Solution:

SOLUTION
Smaller the bond angle. greater is the resultant dipole moment

The dipole moment of 2 dipoles inclined at an angle θ is given by,

μ =√ (x²+y²+2xycosθ?)

cos90=0

∴ The dipole moment is maximum for θ=90⁰

Option 4

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