Solution:
SOLUTION
M1V1+M2V2=MxVx
Where, V1→ Volume of the gicen HCl solution =10ml
M1→[H+]ion concentration in given HCl solution =10−4
V2→Volume of water required
M2→[H+] ion concentration in water =10−7
Mx→[H+] ion concentration required =10−5
Vx→Total volume=(10+V2)
∴(10−4×10)+(10−7×V2)=10−5(10+V2)
Solving, we get,
V2 = 90ml