Solution:
Solution
The molar masses of propane and water are 44 g/mol and 18 g/mol respectively.
44.0 grams of propane corresponds to 1 mole of propane.
According to the balance chemical equation, C3?H8?(g)+5O2?(g)→3CO2??(g)+4H2??O(l),
1 mole of propane gives 4 moles of water.
Thus, the combustion of 44.0 g (1 mole) of propane will give 4 moles of water.
Mass of water obtained =4×18=72.0 g.