NSEC CHEMISTRY

DAILY CHEMISTRY TEST QUESTIONS

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1 Basic Principles of Organic Chemistry

Conversion of CH4 to CH3Cl is an example of ______ reaction .

1) nucleophilic substitution
2) electrophilic substitution
3) Free radical addition
4) Free radical substitution.

Option 1

Option 2

Option 3

Option 4 Solution:

When methane gas is treated with chlorine in the presence by sunlight, one hydrogen of methane replaced by the chlorine atom and forms methyl chloride. The mechanism involved in this reaction is free radical mechanism. So it is an example of free radical substitution reaction.

2 Basic Principles of Organic Chemistry

Which of the following compounds will exhibit geometrical isomerism?

1) 1 - Phenyl - 2 - butene
2) 3 - Phenyl - 1- butene
3) 2 - Phenyl - 1- butene
4) 1, 1 - Diphenyl - 1 - propane

Option 1 Solution:

SOLUTION

We know that for Geometrical Isomer we need a double bond between carbon atom (this restricts rotation) and carbon atom at two sides must be linked to two different groups.

Option 2

Option 3

Option 4

3 Solutions

10 mL of 2(M)NaOH solution is added to 200mL of 0.5(M) of NaOH solution. What is the final concentration?

1) 0.3 M
2) 0.6 M
3) 0.5 M
4) 0.4 M

Option 1

Option 2

Option 3 Solution:

Solution

Number of moles of NaOH in 10 mL of 2 M solution

=(10 mL / 1000 mL/L)×2 mol/L=0.02 mol

Number of moles of NaOH in 200 mL of 0.5 M solution

=(200 mL / 1000 mL/L) × 0.5mol/L=0.1 mol

Total number of moles of NaOH=0.02+0.1=0.12 mol

Total volume =10+200=210 mL =0.210 L

Final concentration =0.210 L / 0.12 mol = 0.57 M

Option 4

4 States of Matter

On a ship sailing in a pacific ocean where temperature is 23.4^oC, a balloon is filled with 2L air. What will be the volume of the balloon when the ship reaches Indian Ocean, where temperature is 26.1^oC

1)1.37L
2) 4.0 L
3) 2.02L
4) 2.94L

Option 1

Option 2

Option 3 Solution:

Solution

$\cfrac { { V }_{ 2 } }{ { T }_{ 2 } } =\cfrac { { V }_{ 1 } }{ { T }_{ 1 } } \Longrightarrow { V }_{ 2 }=\cfrac { 2L\times 299.1 }{ 296.4 } =2.02L$

Option 4

5 D and F Block Elements

Anhydrous FeSO4 is

1) brown

2) green

3) white

4) black

Option 1

Option 2

Option 3 Solution:

Option 4

6 Hydrogen

Unstable hardness of water is due to the presence of:

1) CaCl₂, MgSO₄
2) Ca⁺², Mg⁺²
3) K⁺, CaCO₃
4) Ca(HCO₃)₂, Mg(HCO₃)₂

Option 1

Option 2

Option 3

Option 4 Solution:

SOLUTION

NaCl (and other ionic compounds) dissolve more in H₂O than in D₂O as the dielectric constant of H₂O (78.39) is higher than the dielectric constant of D₂O(78.06). This is due to lower molar mass of H₂O as compared to that of D₂O

7 Haloalkanes and Haloarenes

Which of the following nucleophiles is going to promote an S_N2? reaction?

1 NaI
2) Water
3) NH₄?Cl
4) MeONa

Option 1 Solution:

SOLUTION

The correct order of strength of nucleophilies mentioned above is:

CH₃?ONa > NaI > NH_4?Cl > H₂?O

A nucleophile in context of Substitution Nucleophilic reactions (S_N1? or S_N2?) is stronger when it has more affinity to attach to the positive site.

SN2? reaction also depends on steric factor,so NaI is better nucleophile than MeONa

Option 2

Option 3

Option 4

8 Electrochemistry

E0(Ni₂₊/Ni)=−0.25volt, E0(Au³⁺/Au)=1.50volt . The standard emf of the voltaic cell. Ni(s)|Ni²⁺(aq)(1.0M)|| Au³⁺(aq)(1.0M)|Au(s)Ni(s)|Ni(aq)2+(1.0M)||Au(aq)³⁺(1.0M)|Au(s) is:

1) 1.25 volt
2) - 1.75 volt
3) 1.75 volt
4) 4.0 volt

Option 1

Option 2

Option 3 Solution:

SOLUTION

E0cell=(E0Ni/Ni2++E0Au3+/Au)

=(0.25+1.50)=1.75volt

Option 4

9 Solid State

The pyknometric density of sodium chloride crystal is 2.165×10³ kg m⁻³ while its X−ray density is 2.178×10³ kg m⁻³. The fraction of unoccupied sites in sodium chloride crystal is:

1) 5.96
2) 5.96×10⁻²
3) 5.96×10⁻¹
4) 5.96×10⁻³

Option 1

Option 2

Option 3

Option 4 Solution:

Solution

First density = $2.165\times 10^{3}$

Difference of density $=( 2178-2165)\ Kg/m^3=13$ $Kg/m^{3}$

Therefore,

fraction of unoccupied site =

$\dfrac{13}{2178}$

$= 0.00596 = 5.96 \times$

$10^{-3}$

10 Haloalkanes and Haloarenes

The reaction of 1-hexene with HBr in presence of peroxide yields 1-bromo cyclohexane. The mechanism of the reaction involves :

1 attack on alkene by a Br+ ion
2) attack on alkene by a bromide ion
3) attack on alkene by a bromine free radical
4) None of these

Option 1

Option 2

Option 3 Solution:

SOLUTION

The reaction of 1-Hexene with HBr in presence of peroxide yields 1-bromo cyclohexane.

The mechanism of the reaction involves an attack on alkene by a bromine atom. The reaction proceeds through a free radical mechanism.

In the presence of peroxide, bromine free radical is generated. This bromine free radical then attacks alkene.

Option 4

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