Solution

Because the oxidation state of oxygen in $${ H }_{ 2 }{ O }_{ 2 }$$ is $$-1$$ which can be oxidized to $$'O'$$ oxidation state by removing an $${ e }^{ - }$$ or else can be reduced by adding an $${ e }^{ - }$$ and oxidation state would be reduced to $$-2$$ oxidizing agent means oxidizing others itself getting reduced.

Solution

CH₃CHO + 2[H] → CH₃-CH₂OH [ in presence of Na/ Alcohol]

SOLUTION

There is one peroxy linkage S−O−O−S. Hence two of the eight oxygen atoms have -1 oxidation state and rest 6 have -2 oxidation state. Let the total oxidation state of S be x

then 2×1+x+6×(−2)+2×(−1)=0

or 2+x−12−2=0

x=+12

SOLUTION

Both hexane and 3-methylpentane have formula of C₆H₁₄,  Compounds having same molecular formula but different structures due to the different arrangement of atoms or group of atoms in the parental chain are called chain isomers. Hexane and 3-methylpentane are chain isomers.

SOLUTION

C₄H₁₀O satisfies the general formula C_nH_2n+2O

It is either a monohydric alcohol or an ether.

Four structural isomers of alcohol and three structural isomers of ethers are possible. They are:

1. butan-1-ol
2. butan-2-ol
3. 2-methyl-propan-1-ol
4. 2,2dimethyl-propan-2-ol
5. diethyl ether
6. methyl 1-propyl ether
7. methyl 2-propyl ether

Solution

At constant pressure, V1 /T1 = V2 /T2 ; 

V1 = 300 dm3 ;  V2 = ?, T1 = 300K, T2 = 273 – 33 = 240 K; 

V2 = (V1 /T1 ).T2 = (300/300) ´ 240 = 240 dm³   

decrease in volume = 300 – 240 = 60 dm³