Solution:
Solution
The voltage can be written as,
$$V = 5\left( {\sin \omega t + \frac{\pi }{2}} \right)$$
The angle between the voltage and the current is $$90^\circ $$.
The power dissipated in the circuit is given as,
$$P = {V_{rms}}{I_{rms}}\cos \phi $$
$$ = {V_{rms}}{I_{rms}}\cos 90^\circ $$
=$$0$$
Thus, the power dissipated in the circuit is $$0$$.