NSEP PHYSICS

DAILY PHYSICS TEST QUESTIONS

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1 Properties of Bulk Matter

A diving bell is to be used at great depths and so its walls are made very thick. The main reason for this is that

(1) The water is much colder at great depths
(2) Water pressure increases with depth of the water
(3) The density of the water is much greater at great depths
(4) Ice forms in deep water and could crush the bell

Option 1

Option 2 Solution:

Option 3

Option 4

2 Electrostatics

A sphere carrying a charge of 0.01 C is kept at rest without falling down, touching a wall by applying an electric field 100 N/C. If the coefficient of friction between the sphere and the wall is 0.2, the weight of the sphere is:

1) 2 kg
2) 2 N
3) 20 N
4) 0.2 N

Option 1

Option 2

Option 3

Option 4 Solution:

Solution

As the sphere is at rest N=Eq and f =mg
N = 100×0⋅01
N = 1Newton
we know that f=μN (maximum static function is μN)
f = 0⋅2×1
f=0⋅2
Condition of equlibrium:

f = Mg

⇒0⋅2=mg
∴ weight =0⋅2N
∴ Maximum weight which can be stopped is 0⋅2N
∴ weight must be ≤0⋅2N
From the given options , only( 4) is ≤0.2

3 Current Electricity

A galvanometer with a coil resistance of 100 Ω gives a full scale deflection when a current of 1 mA is passed through it. The resistance of the shunt needed in ohm to convert this galvanometer into an ammeter of range 10 A is nearly

1) 0.01
2) 0.001
3) 0.1
4) 0.099

Option 1 Solution:

Solution

Let the resistance be connected be X

=$$\dfrac { 100x }{ 100+x } =Req$$

= $$100\left( \dfrac { 100x }{ 100+x } \right) ={ 10 }^{ -3 }(100)$$

= 10000x=100+x

=9999x=100

= $$x=0.01\Omega $$

Option 2

Option 3

Option 4

4 Gravitation

A satellite orbits at a height h above the Earth's surface. Let R be the Earth's radius. If Ve is the escape velocity and Vo is the orbital velocity of the satellite orbiting at a height h << R, then

1) Vo² = 2 Ve²
2) Ve²= 2 Vo²
3)Ve = 2 Vo
4) Ve = Vo

Option 1

Option 2 Solution:

Option 3

Option 4

5 Magnetic Effects of Current and Magnetism

At the mid-point along the length of a long solenoid, the magnetic field is equal to x, If the length of the solenoid is doubled and the current is reduced to half, the field at the new mid-point will be nearest to:

(1) x/2
(2) x/4
(3) x
(4) 2x

Option 1

Option 2 Solution:

Solution

x/4

Option 3

Option 4

6 Dual Nature of Matter and Radiation

The Kα X-ray emission line of tungsten occurs at λ = 0.021nm. The energy difference between K and L levels in this atom is about

1) 0.51MeV
2) 1.2MeV
3) 59keV
4) 13.6eV

Option 1

Option 2

Option 3

Option 4 Solution:

Solution

Line $$\displaystyle { K }_{ \alpha }$$ corresponds to transfer of electron from L-shell to K-shell.
Here, $$\displaystyle \lambda =0.021nm = 2.1\times 10^{-11}\ m$$

We know that $$\lambda = \dfrac{hc}{E (in \ Joule)}$$
$$\displaystyle \lambda=\frac { hc }{ E (in \ Joule)} =\frac { hc }{ e\times E\left( in \ eV \right) } $$
$$\displaystyle \Rightarrow \quad E\left(in \ eV \right) =\frac { hc }{ e\lambda } =\frac { 6.63\times { 10 }^{ -34 }\times 3\times { 10 }^{ 8 } }{ 1.6\times { 10 }^{ -19 }\times 2.1\times { 10 }^{ -11 } } eV$$
$$\displaystyle E(in \ eV)=5.9\times { 10 }^{ 4 }eV=59keV$$

7 Wave Optics

In a double slit experiment, the two slits are 1 mm apart and the screen is place 1 m away. A monochromatic light of wavelength 500 nm is used. What will be the width of each slit for obtaining ten maxima of double slit within the central maxima of single slit pattern?

1) 0.5mm
2) 0.02mm
3) 0.2mm
4) 0.1mm

Option 1

Option 2

Option 3 Solution:

Solution

$$d = 10^{-3}\:m$$
$$D=1\:m$$
$$ \lambda = 500 \times 10^{-9}\:m$$
The width of central maxima in a single slit diffraction: $$\dfrac{2 \lambda D}{a}$$
Fringe width in double slit pattern: $$\beta = \dfrac{\lambda D}{d}$$
Given,
$$10 \beta = \dfrac{2 \lambda D}{a}$$
$$ \Rightarrow 10 \dfrac{\lambda D}{d} = \dfrac{2 \lambda D}{a}$$
$$ \Rightarrow a =\dfrac{d}{5}\:mm= 0.2\:mm$$

Option 4

8 Physical world and measurement

Consider the following statements about dimensions :

P: Force = acceleration due to gravity x mass

Q :Electric charge = current x time

R : Magnetic flux = Electric voltage x time

The correct statements are:

(1) R, P only
(2) P, Q and R
(3) P, Q only
(4) Q, R only

Option 1

Option 2

Option 3 Solution:

Option 4

Which quantity remains conserved as external torque is zero :

(1) linear momentum

(2) angular momentum

(3) kinetic energy

(4) potential energy

Option 1

Option 2 Solution:

Option 3

Option 4

10 Ray Optics

A concave mirror is placed over a beaker containing water of (� = 1.33) and image of the object placed at the bottom of beaker is formed at a distance of 25 cm from the top then focal length of the mirror is

(1)10 cm (2) 15 cm

(3) 20 cm (4) 25 cm

Option 1

Option 2

Option 3 Solution:

Option 4

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