Solution:
Solution
charges on the capacitor are
q1=(30)(2)=60 μF
q2=(20)(3)=60 μF
⇒ q1=q2=q (let)
When s3 is closed, due to attraction with opposite charge, no flow of charge take place through s3 Therefore, potential difference across capital plates remain unchanged i.e. v1=30 v and v2 = 20 v