NSEP PHYSICS

DAILY PHYSICS TEST QUESTIONS

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1 Electromagnetic Waves

A plane electromagnetic wave of frequency 20 MHz travels through a space along x direction. If the electric field vector at a certain point in space is 6 V m⁻¹, what is the magnetic field vector at that point?

1) 2×10⁻⁸T
2) 1/ 2×10⁻⁸T
3) 2T
4) 1 / 2T

Option 1 Solution:

Solution

Velocity of EM wave $$v = 3\times 10^{8}$$ $$m/s$$

Electric field vector $$E = 6$$ $$V/m$$

Thus magnetic field vector $$B = \dfrac{E}{v}$$

$$\therefore$$ $$B = \dfrac{6}{3\times 10^8} =2\times 10^{-8}$$ $$T$$

Option 2

Option 3

Option 4

2 Motion of System of Particles and Rigid Body

A Uniform chain of length L and mass M is laying on a smooth table and ½ of its length is having down over the edge of the table. If g is the acceleration due to gravity, the work done to pull the hanging part on the table is:

1) mgL/18
2) mgL/8
3) mgL/9
4) mgL/32

Option 1

Option 2 Solution:

Option 3

Option 4

3 Ray Optics

The velocity of light in a medium is 2 x 10⁸ m/s. The refractive index of the medium is:

(1) 1.0
(2) 1.5
(3) 1.4
(4) 2.3

Option 1

Option 2 Solution:

Option 3

Option 4

4 Gravitation

If the escape velocity of a rocket from the surface of the Earth is ve , then the escape velocity of the same rocket from the surface of a planet whose acceleration due to gravity as well as radius are 5 times that of the Earth is

1) v_e / 5
2) 5 v_e
3) 25 v_e
4) v_e

Option 1

Option 2 Solution:

The escape velocity of an object from the surface of a planet of radius R and acceleration due to gravity g is given by
V_e =Ö2gR

Increasing both g and R by a factor of 5 will result in the escape velocity increasing by a factor of 5. So, the answer is 5 v_e.

Option 3

Option 4

5 Electronic Devices

In a good conductor the energy gap between the conduction band and valence band is:

(1) Wide
(2) Infinite
(3) Zero
(4) Narrow

Option 1

Option 2

Option 3 Solution:

Option 4

6 Capacitance

A 110 V, 60 W lamp is run from a 220 V AC mains using a capacitor in series withe the lamp, instead of a resistor then the voltage across the capacitor is about:

1) 110 V

2) 190 V

3) 220 V

4) 311 V

Option 1

Option 2 Solution:

Solution

The correct option is similar to B

Given,

$$110 V, 60 W$$ lamp is run from a $$220 V$$

The lamp is close to an ideal resistance giving voltage $$( Vr )$$ at phase angle $$\theta = 0^o$$;

The capacitor is close to an ideal reactance giving voltage $$( Vc )$$

at phase angle $$\theta = 90^o $$

The voltages across the lamp and capacitor will be in quadrature with one another,

and the supply voltage $$( Vs )$$ will be the PHASOR SUM of $$Vr and Vc$$

$$\Rightarrow Vs^2 = Vr^2 + Vc^2 $$

$$\Rightarrow Vc^2 = Vs^2 - Vr^2$$

$$⇒ Vc^2 = 220^2 - 110^2$$

$$\Rightarrow Vc^2 = 36300$$

$$\Rightarrow Vc = \sqrt{ 36300 }$$

$$\Rightarrow Vc \approx 191 V $$

Option 3

Option 4

7 Electrostatics

A charge is kept at the centre of a shell. Shell has charge Q uniformally distibuted over its surface and radius R. The force on the central charge due to the shell is :

1) towards left
2) towards right
3) upward
4) zero

Option 1

Option 2

Option 3

Option 4 Solution:

Solution

Electric field at the centre of shell is zero when charge is uniformally distributed over surface of shell .

Hence the force on the charge at the centre is zero.

8 Gravitation

A satellite orbits at a height h above the Earth's surface. Let R be the Earth's radius. If Ve is the escape velocity and Vo is the orbital velocity of the satellite orbiting at a height h << R, then

1) Vo² = 2 Ve²
2) Ve²= 2 Vo²
3)Ve = 2 Vo
4) Ve = Vo

Option 1

Option 2 Solution:

Option 3

Option 4

9 Electromagnetic Induction

The magnetic flux through a coil perpendicular to its plane and directed into paper is varying according to the relation ?=(2t²+4t+6) mWb. The emf induced in the loop at t = 4 s is:

1) 0.12 V
2) 2.4 V
3) 0.02 V
4) 1.2 V

Option 1

Option 2

Option 3 Solution:

Solution

Given, $$\phi= (2t^2 + 4t + 6) mWb$$
As, $$\displaystyle \epsilon = \frac{d\phi}{dt} =\frac {d}{dt} \,(2t^2 + 4t + 6) \times 10^{-3} Wb\,s^{-1}$$
$$ = (4t + 4) \times 10^{-3} V$$
At $$t=4 \,s$$
$$\epsilon$$ =(4 x 4 + 4) x 10$$^{-3}$$ V = 20 x 10$$^{-3}$$ V = 0.02V

Option 4

10 Properties of Bulk Matter

On applying a stress of xN/m², the length of wire of some material gets doubled. Value of Young's modulus for the material of and wire in N/m², is (assume Hooke's law to be valid and go for approx. results)

1) 2x
2) x
3) x/2
4) Insufficient information

Option 1

Option 2 Solution:

Solution

Here strain =1 , stress = $$x\ N/m^2$$

young modulus y=$$\dfrac{stress}{strain}=x\ N/m^2$$

Option 3

Option 4

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