NSEP PHYSICS

DAILY PHYSICS TEST QUESTIONS

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1 Properties of Bulk Matter

An elastic spring doubles its unstretched length to 16cm without exceeding its elastic limit when a force of 28N is applied to it. When a force of 7N is applied, the length of the spring is

(1) 2 cm
(2) 4 cm
(3) 7 cm
(4) 8 cm

Option 1

Option 2 Solution:

Option 3

Option 4

2 Kinematics

A Projectile is given an initial velocity of ( i+2j) m/s, + where i is along the ground and j is along the vertical. If g = 10 m/s², the equation of its trajectory is
1) y = x − 5x² (2) (3) (4)
2) y = 2x − 5x²
3) 4y = 2x − 5x²
4) 4y = 2x − 25x²

Option 1

Option 2 Solution:

Solution

Equation of trajectory

y= 2x -5x²

Option 3

Option 4

3 Ray Optics

A lamp of luminous intensity 20Cd is hanging at a height of 40 cmcm from the center of a square table of side 60 cm. The illuminance at the midpoint of the side of the table will be

1) 64 lux
2) 100 lux
3) 125 lux
4) 32 lux

Option 1 Solution:

Solution

Luminous intensity, L = 20 Cd

Distance of source from center of table, h = 40 cm

Distance of center of table to midpoint of side of table = a/2 = 30 cm

Total distance between source and point, d = $$\sqrt{(h^{2}+(a/2)^{2})}$$ = 50 cm

As per attached picture Cos (theta) = 4/5

Lambert's law, $$I = L Cos \theta / d^{2}$$

$$\rightarrow I = 20 (4/5) / (0.5)^{2}$$

$$\rightarrow I = 64 lux$$

Option 2

Option 3

Option 4

4 Electromagnetic Waves

The capacity of a parallel plate air capacitor is 2μF and voltage between the plates is changing at the rate of 3V/S. The displacement current in the capacitor is:

1) 2μF
2) 3μF
3) 5μF
4) 6μF

Option 1

Option 2

Option 3

Option 4 Solution:

Solution

Displacement current in capacitor $$i = A\epsilon_o \dfrac{dE}{dt}$$

Or $$i = \dfrac{A\epsilon_o}{l} \dfrac{d(El)}{dt}$$ where $$l$$ is the separation between the two plates.

Potential difference between the two plates $$V = El$$

$$\implies$$ $$i = C \dfrac{dV}{dt}$$ where capacitance of the capacitor is $$C = \dfrac{A\epsilon_o }{l}$$

$$\therefore$$ $$i = 2\mu F \times 3 V/s = 6\mu A$$

5 Electromagnetic Induction

An alternating voltage is connected in series with a resistance R and an inductance L. If the potential drop across the resistance is 200 volt and across the inductance is 150 volt, the applied voltage is

1) 350 volt
2) 250 volt
3) 500 volt
4) 300 volt

Option 1

Option 2 Solution:

Solution

$$Total\quad PD\quad =\quad \sqrt { PD_{ Inductance }^{ 2 }+PD_{ resistance }^{ 2 } } \\$$

$$ PD\quad =\quad \sqrt { { 150 }^{ 2 }+{ 200 }^{ 2 } } $$

$$=250V$$

Option 3

Option 4

6 Kinematics

A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to v(x) = βx-2n, where β and n are constants and x is the position of the particle. The acceleration of the particle as a function of x, is given by
1) -2nβ² x^-4n+1
2) -2nβ² x^-2n-1
3) -2nβ² x^-4n-1
4) -2β² x^-2n+1

Option 1

Option 2

Option 3 Solution:

Solution

Option 4

7 Kinetic Theory of gases

A quill tube contains a mercury column of length 19 cm. The length of air column is 24 cm when it is held vertically. On inverting it with its open end downwards the length of air column will be_______cm. (atmospheric pressure = 76 cm of Hg)

1) 20 cm
2) 30 cm
3) 40 cm
4) 35 cm

Option 1

Option 2

Option 3 Solution:

Solution

The pressure of air inside while held vertically= 76 + 19 = 95 cm of Hg
Having volume= 24A (A is the area of crossection)
When downside,
pressure=76−19=57
LET height be x
Hence, by having temperature constant,PV= constant, we get
24A∗95=xA∗57
x=40

Option 4

The temperature of 100 g of water is to be raised from 24� C to 90� C by adding steam to it. Calculate the mass of the steam required for this purpose (latent heat of steam = 540 k Cal/kg)
1.10 g
2. 11 g
3. 12 g
4. 15 g

Option 1

Option 2

Option 3 Solution:

Option 4

9 Capacitance

A circuit has a self-inductance of 1H and carries a current of 2A. To prevent sparking, when the circuit is switched off, a capacitor which can withstand 400V is used. The least capacitance of capacitor connected across the switch must be equal to

1) 50μF

2) 25μF

3) 100μF

4) 12.5μF

Option 1

Option 2 Solution:

Solution

Energy stored in capacitor = energy stored in inductance

i.e., $$\dfrac { 1 }{ 2 } C{ V }^{ 2 }=\dfrac { 1 }{ 2 } { LI }^{ 2 }$$
$$\Rightarrow C=\dfrac { { LI }^{ 2 } }{ { V }^{ 2 } } =\dfrac { 1\times { \left( 2 \right) }^{ 2 } }{ { \left( 400 \right) }^{ 2 } } =25\mu F$$

Option 3

Option 4

10 Current Electricity

1 amp. current flow is a circuit when a cell is connected to 1 ohm resistance and 0.5 amp. to a 3 ohm resistance. The internal resistance of cell is :

(1) 2 ohm

(2) 1.0 ohm

(3) 1.5 ohm

(4) 0.5 ohm

Option 1

Option 2 Solution:

Option 3

Option 4

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NSEP PHYSICS

DAILY PHYSICS TEST QUESTIONS

Question Bank

Solution

Solution

Solution

Solution

Solution

i.e., $$\dfrac { 1 }{ 2 } C{ V }^{ 2 }=\dfrac { 1 }{ 2 } { LI }^{ 2 }$$ $$\Rightarrow C=\dfrac { { LI }^{ 2 } }{ { V }^{ 2 } } =\dfrac { 1\times { \left( 2 \right) }^{ 2 } }{ { \left( 400 \right) }^{ 2 } } =25\mu F$$

MOCK TEST

i.e., $$\dfrac { 1 }{ 2 } C{ V }^{ 2 }=\dfrac { 1 }{ 2 } { LI }^{ 2 }$$
$$\Rightarrow C=\dfrac { { LI }^{ 2 } }{ { V }^{ 2 } } =\dfrac { 1\times { \left( 2 \right) }^{ 2 } }{ { \left( 400 \right) }^{ 2 } } =25\mu F$$