Solution:
SOLUTION
$$ E - W_0 = \frac{ 1}{2} mv^2 $$
First case, $$ 2 W_0 = W_0 = \frac{ 1}{2} mv_1^2 $$ ..(i)
Second case, $$ 5 W_0 - W_0 = \frac{ 1}{2} mv_2^2 $$ ..(ii)
Therefore, from Eqs. (i) and (ii),
$$ \frac{ 2 W_0 - W_0 }{ 5 W_0 - W_0 } = \frac{ v_1^2 }{ v_2^2 } $$ or $$ \frac{ v_1 }{ v_2 } = \frac{ 1}{2} $$