Solution:
Solution

The air filled capacitance , $$C=\dfrac{A\epsilon_0}{d}=9 pF$$
According to question there are two capacitor with capacitances $$C_1 $$ and $$ C_2$$ . and they are in series .
Here, $$C_1=\dfrac{Ak_1\epsilon_0}{(d/3)}=9 \dfrac{A\epsilon_0}{d}=9C $$ as $$k_1=3$$
and $$C_2= \dfrac{Ak_2\epsilon_0}{(2d/3)}=9 \dfrac{A\epsilon_0}{d}=9C $$ as $$k_2=6$$
The equivalent capacitance, $$C_{eq}=\dfrac{C_1C_2}{C_1+C_2}=\dfrac{(9C)(9C)}{9C+9C}=\dfrac{9}{2}C=(9/2) 9=40.5 pF$$