Solution:
Solution
The speed of light in the medium, $$v=\dfrac{c}{\sqrt{\mu_r\epsilon_r}}$$ $$= 0.5 \times\dfrac{3\times 10^{8}m/s}{\sqrt{(4)(9)}}$$ $$=10^{8}m/s$$
Hence, the magnitude of electric field $$=vB=0.5 \times 10^8m/s\times 4.2\times 10^{-8}T$$ $$=2.1 Vm^{-1}$$