Solution:
Solution
Distance between the slits, md=0.28×10−3 m
Distance between the slits and the screen, D=1.4m
Distance between the central fringe and the fourth (n=4) fringe,
u = 1.2×10−2 m
In case of a constructive interference, we have the relation for the distance between the two fringes as:
u = nλD/d
⇒λ = ud/nD=6×10−7m = 600nm