Solution:
Solution
Initial temperature T=27oC=27+273K=300K.
Final temperature T′=127oC=127+273K=400K.
Initial volume =V
Final volume =V′
V′? / V =T′ / T ?= 400 / 300 ?= 1.33
The fraction of air originally present in the bottle that is expelled is
(V′−V) /V ?= (1.33−1) /1 ? = 0.33 %