Solution:
Solution
Moles of acetic acid adsorbed =(0.5−0.49)×100? /1000=10−3 moles.
So, molecules adsorbed =10−3×6.023×1023 = 6.023×1020
Surface area of charcol=4.73×104 cm2.
Surface area of charcol adsorbed by each molecule = (4.73×104) / 6.023×1020 = 7.8×10−17cm2