Solution:
Solution
In the give metal bicarbonates, the anion (bicarbonate ion) is same. Hence the solubility will depend on the size of anion. The size of $$Na^+$$ ion is smaller than that of $$K^+$$ ion. Hence sodium bicarbonate has high lattice energy and lower solubility than potassium bicarbonate. Similarly, the size of $$Mg^+$$ ion is smaller than that of $$Ca^+$$ ion. Hence magnesium bicarbonate has high lattice energy and lower solubility than calcium bicarbonate.