Solution:
Solution:
Let $$a_1 $$ and $$ a_2$$ be amplitudes of the two waves. For maximum intensity
$$\hspace30mm I_{max} = (a_2 + a_2)^2$$
For minimum intensity
$$\hspace30mm I_{min} = (a_2 - a_2)^2$$
Given, $$\hspace20mm \frac{I_{max}}{I_{min}} = \frac{25}{1} = \frac{((a_1 + a_2)^2)}{(a_1 - a_2)^2}$$
$$\Rightarrow \hspace20mm \frac{a_1 + a_2}{a_1 - a_2} = \frac{5}{1} \Rightarrow \frac{a_1}{a_2} = \frac{3}{2}$$
$$\therefore \hspace30mm \frac{I_1}{I_2} = \frac{a_1^2}{a_2^2} = \big(\frac{3}{2}\big)^4 = \frac{9}{4}$$