Solution:
Solution:
$$\Delta P$$ of one particle $$ = mv \cos45^{\circ} \times 2$$
Force $$ = N \Delta_{p} $$
$$ = 10^{23} \times\frac{mv}{\sqrt{2}} \times2$$
$$ = 10^{23} mv \sqrt{2}$$
Pressure $$ = \frac{10^{23} \times3.23 \times10^{-27} \times10^{3} \sqrt{2}}{ 2 \times10^{-4}}$$
$$ = \frac{10^{23} \times3.32 \times\sqrt{2}}{2} $$
$$ = \frac{10^{3} \times4.7}{2} $$
$$= 2.35 \times10^{3} N/m^{2} $$