JEE PHYSICS

DAILY PHYSICS TEST QUESTIONS

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1 Dual Nature Of Radiation And Matter

A nuclear power plant supplying electrical power to the village uses a radioactive material of half life T years as the fuel. The amount of fuel at the beginning such that the total power requirement of the village is 12.5 % of the electrical power available from the plant at that time. If the plant is able to meet the total power needs of the village for a maximum period of n T years, then the value of n is

1) 1
2) 3
3) 5
4) 7

Option 1

Option 2 Solution:

SOLUTION

Option 3

Option 4

2 Kinematics

A small particle of mass m is projected at an angle θ with the X–axis with an initial velocity v_o in the X–Y plane as shown in the figure. At a time

Option 1

Option 2

Option 3 Solution:

SOLUTION

Option 4

3 Waves

If a progressive wave is represented as y =2 sin $$\pi \left(\frac{t}{2}-\frac{x}{4}\right)$$ where x is in metre and t is in second, then the distance travelled by the wave in 5 s is

1) 5 m
2) 10 m
3) 25 m
4) 32 m

Option 1

Option 2 Solution:

Solution:

Given, y = 3 sin $$\pi = \left(\frac{t}{2}-\frac{x}{4}\right)$$

= 3 sin $$ \left(\frac{\pi t}{2}-\frac{\pi x}{4}\right)$$

Comparing it with standard equation

y = r sin $$ \frac{2\pi}{\lambda}\left(vt-x\right)$$

= r sin $$\left(\frac{2\pi vt}{\lambda}-\frac{2\pi x}{\lambda}\right)$$

We have,$$\frac{2\pi v}{\lambda} = \frac{\pi}{2} $$ or v = $$\frac{\lambda}{4}$$

and $$\frac{2\pi}{\lambda} = \frac{\pi}{4}$$ or $$\lambda = 8m \therefore v =\frac{8}{4} =2 $$ m/s

So, the distance travelled by wave in t second = vt = 2 × 5 = 10 m

Option 3

Option 4

4 Current Electricity

A moving coil Galvanometer of resistance 100W is converted to ammeter by a resistance of 0.1W in the circuit. Galvanometer gives full scale deflection at 100�A. The minimum current in the circuit for maximum deflection is

(1) 100.1 mA (2) 1000.1 mA

(3) 1.001 mA (4) 10.01 mA

Option 1 Solution:

Option 2

Option 3

Option 4

5 Thermal Properties Of Matter

Four rods with different radii r and length / are used to connect two heat reservoirs at different temperature. Which one will conduct most heat ?

1) $$r = 1 \, cm, l = 1 \, m $$
2) $$r = 1 \, cm , l = \frac{1}{2} m$$
3) $$r = 2 \, cm, l = 2 \, m $$
4) $$r = 2 \, cm , l = \frac{1}{2} m$$

Option 1

Option 2

Option 3

Option 4 Solution:

Solution:

$$H = \frac{KAd\theta}{L} \propto \frac{A}{L } = \frac{\pi r^{2}}{L} $$

$$ \left(\frac{A}{L}\right)_{1} = \frac{\pi\left(1\right)^{2}}{1} = 2\pi\,\, units \hspace10mm \left(\frac{A}{L}\right)_{2} = \frac{\pi\left(2\right)^{2}}{\frac{1}{2}} = 8\pi \,\, units.$$

$$ \left(\frac{A}{L}\right)_{3} = \frac{\pi\left(1\right)^{2}}{1} = \pi \,\, units \hspace10mm \left(\frac{A}{L}\right)_{_4 }= \frac{\pi\left(2\right)^{2}}{2} = 2\pi\,\, units$$

So rod (2) will conduct most heat per second.|

6 Magnetic Effects of Current

Yellow light of wavelength 6000Å produces fringes of width 0.8mm in Youngs double slit experiment. If the source is replaced by another monochromatic source of wavelength 7500Å and the separation between the slits is doubled then the fringe width becomes

1) 0.1mm
2) 0.5mm
3) 4.3mm
4) 1mm

Option 1

Option 2 Solution:

Solution:

Fringe width in first case, $$\beta_{1} = \frac{D\lambda_{1}}{d}\quad...\left(i\right) $$

Fringe width in second case, $$\beta_{2}=\frac{D\lambda_{2}}{2d} \quad...\left(ii\right) $$

Divide equation $$\left(ii\right)$$ by $$\left(i\right)$$,

$$ \therefore \frac{\beta_{2}}{\beta_{1}}= \frac{D\lambda_{2}/ 2d}{D\lambda_{1} /d} = \frac{1}{2} \cdot\frac{\lambda_{2}}{\lambda_{1}} $$ or

$$\beta_{2} = \frac{1}{2}\cdot\frac{\lambda_{2}}{\lambda_{1}} \cdot\beta_{1} $$

$$\therefore \beta_{2} = \frac{1}{2}\times\frac{ 7500 Å}{6000 Å} \times 0.8 mm $$

$$= 0.5 mm $$

Option 3

Option 4

7 Semiconductors and Electronic Devices

An n-p-n transistor of current gain 80 in common emitter mode gives emitter current equal to 8.1 mA. The base current is

1) 0.1 $$\mu$$A
2) 0.1 mA
3) 0.01 mA
4) 0.01 $$\mu$$A

Option 1

Option 2 Solution:

Solution:

$$\beta=80$$

$$l_{c}=8.1mA$$

$$\left(\frac{l_{c}}{l_{b}}\right) =80\left(l_{e}=l_{b}+l_{c}\right)$$

$$\left(\frac{l_{e-l_b}}{l_{b}}\right) =80$$

Option 3

Option 4

8 Kinematics

The maximum height reached by a projectile is 4 metres. The horizontal range is 12 metres. Velocity of project in ms^–1 is (g – acceleration due to gravity)

Option 1 Solution:

SOLUTION

Option 2

Option 3

Option 4

9 Dual Nature Of Radiation And Matter

A monochromatic light of frequency $$v = \frac{1}{6.63} \times 10^{16}$$ Hz is produced by a laser. The power emitted is $$P = 10^{-2}$$ W. The average number of photos per second emitted by the source is

1) $$\frac{1}{(6.63)^2} \times 10^{16}$$
2) $$(6.63)^2 \times 10^{16}$$
3) $$10^{20}$$
4) $$10^{16}$$

Option 1

Option 2

Option 3

Option 4 Solution:

10 Thermal Properties Of Matter

A solid cylinder of radius R made of a material of thermal conductivity K₁ is surrounded cylindrical shell of inner radius R and outer radius 2R made of a material of thermal conductivity K₂. The two ends of the combined system are maintained at two different temperatures. Then there is no loss of heat across the cylindrical surface and the system is in steady state. The effective thermal conductivity of the system is

Option 1

Option 2

Option 3

Option 4 Solution:

SOLUTION

If K is the effective thermal conductivity then,

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