Solution:
Solution
$$\tau =NIA\, B\, sin \, \theta$$
Here, $$N=25$$,
$$I=10\, A$$,
$$B=0.9 \, T$$,
$$\theta =30^{\circ}$$
$$A=a^{2}=12 \times 10^{-2} \times 12\times 10^{-2}$$
$$144 \times 10^{-4}\, m^{2}$$
$$\therefore \tau=25 \times 10 \times = 144\times 10^{-4}\times 0.9\times sin \, 30^{\circ}$$
$$=16.\, N\,m$$
