1 Rotational Motion
The moment of inertia of a ring about an axis passing through the centre and perpendicular to its plane is 'I'. It is rotating with angular velocity $$'\omega'$$. Another identical ring is gently placed on it so that their centres coincide. If both the rings are rotating about the same axis then loss in kinetic energy is
1) $$\frac{I \omega^2}{2}$$ 2) $$\frac{I \omega^2}{4}$$ 3) $$\frac{I \omega^2}{6}$$ 4) $$\frac{I \omega^2}{8}$$
Solution:
$$\frac{I \omega^2}{4}$$
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