Solution:
Solution:
Total length of sonometer wire, l = 110 cm = 1.1 m
Length of wire is in ratio, 6:3:2 i.e. 60 cm, 30 cm, 20 cm.
Tension in the wire, T = 400 N
Mass per unit length, m = 0.01 kg
Minimum common frequency = ?
As we know,
Frequency, $$v = \frac{1}{21}\sqrt{\frac{T}{m}} = \frac{1000}{11}Hz$$
Similarly, $$v_{1}^{ }=\frac{1000}{6}Hz$$
$$v_{2}^{ }=\frac{1000}{3}Hz$$
$$v_{3}^{ }=\frac{1000}{2}Hz$$
Hence common frequency $$= 1000\, Hz$$
