1 Semiconductors and Electronic Devices
An n-p-n transistor of current gain 80 in common emitter mode gives emitter current equal to 8.1 mA. The base current is
1) 0.1 $$\mu$$A 2) 0.1 mA 3) 0.01 mA 4) 0.01 $$\mu$$A
Solution:
$$\beta=80$$
$$l_{c}=8.1mA$$
$$\left(\frac{l_{c}}{l_{b}}\right) =80\left(l_{e}=l_{b}+l_{c}\right)$$
$$\left(\frac{l_{e-l_b}}{l_{b}}\right) =80$$
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