1 Rotational Motion
Distance of the centre of mass of a solid uniform cone from its vertex is $$z_0$$ If the radius of its base is R and its height is h, then $$z_0$$ is equal to
1) $$\frac{3h}{4}$$ 2) $$\frac{h^2}{4R}$$ 3) $$\frac{5h}{8}$$ 4) $$\frac{3h^2}{8R}$$
Solution:
Centre of mass of uniform solid cone of height h is at a height of $$\frac{h}{4}$$ from base. Therefore from vertex it's $$\frac{3h}{4}.$$
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