1 Magnetic Effects of Current
An 8cm long wire carrying a current of 10A is placed inside a solenoid perpendicular to its axis. If the magnetic field inside the solenoid is 0.3T, then magnetic force on the wire is 1) 0.14N 2) 0.24N 3) 0.34N 4) 0.44N
Solution:
$$F=IlB sin \theta$$
Here, $$\theta=90^{\circ}$$, $$I=10\,A$$,
$$l=8\,cm=8\times10^{-2}\,m$$, $$B=0.3\, T$$
$$\therefore F=10\times8\times10^{-2}\times0.3\times sin90^{\circ}$$
$$=0.24\, N $$
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