Solution:
Solution:
Given, $$ I=0.6\,m $$ $$ r=1\,cm $$
$$ N=600 $$ $$ i=6A $$
$$ \Rightarrow $$ $$ {{B}_{inside}}={{\mu }_{0}}ni $$
$$ =4\pi \times {{10}^{-7}}\times \frac{600}{0.6}\times 6 $$
$$ =4\pi \times {{10}^{-7}}\times 36\times {{10}^{3}} $$
$$ =7.54\times {{10}^{-3}}\,T $$
