1 Sequences and Series
If n geometric means between a and b be G1,G2,G3,.......,Gn, and a geometric mean be G , then the true relation is 1) G1.G2 …….Gn = G 2) G1.G2 …….Gn = G1/n 3) G1.G2 …….Gn = Gn 4) G1.G2 …….Gn = G2/n
SOLUTION
Here G = (ab)1/2 and G = ar1 , G2 = ar2 , ……. G = arn
Therefore G1,G2,G3,.......,Gn
= anr 1+2+…+n = anrn(n+1)/2
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