Solution:
Solution
molality of aqueous solution = 5.2 mol kg-1
Therefore, the number of moles of methyl alcohol in 1 kg of solvent (water) = 5.2 mol
And the number of moles of solvent (water) = weight / molar mass = 1000 g / 18 g mol-1 = 55.55 mol
Hence:
Mole fraction of methyl alcohol = nMeOH /nMeOH + nwater = 5.2 / 55.55 + 5.2 = 0.08559
