Solution:
Solution
$$CH_3COOH\xrightarrow { A }CH_3COCl$$ This is the formation of acyl from the carboxylic acid by chlorination of the OH group of $$CH_3COOH$$ by the reagent $$A$$, which is $$ SOCl_2$$,
$$CH_3COCl \xrightarrow{B}CH_3CHO$$, This is the Rosenmund reaction for the formation of aldehyde by the reduction by the reagent $$H_2/Pd-BaSO_4$$. (B)
