Solution:
Solution
Gram molecular weight of N2O3 is 76 g.
76 g of N2O3 contains - 6.023×1023 molecules.
∴ Weight of 4.82×1020 molecules=
15 mg of N2O3 = 0.015g
∴ Total weight of N2O3 = 0.061+0.015 = 0.076g
76 g occupies 22.4 L at STP.
0.076 g occupies at STPSTP =(0.076×22.4) / 76
=0.022L
