1 Rotational Motion
A hoop of radius r and mass m rotating with an angular velocity ω0 is placed on a rough horizontal surface. The initial velocity of the centre of the hoop is zero. What will be the velocity of the centre of the hoop when it ceases to slip ?
1) (rω0)/4 2) (rω0)/3 3) (rω0)/2 4) rω0
SOLUTION : From law of conservation of momentum Li = Lf Iω0 = Iω + mvr And v = ωr m r2 ω0 = mr2ω + mvr = 2mvr v=(rω0)/2
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