1 Work Power Energy
A bomb of 12 kg divides in two parts whose ratio of masses is 1:4. If kinetic energy of smaller part is 288 J, then momentum of bigger part in kgm/sec will be
1) 37 2) 72 3) 108 4) none
SOLUTION:−If v is the velocity of smaller particle then velocity of bigger particle will b v/4 from conservation of momentum Kinetic energy of smaller part=½ mv2=288 J Kinetic energy of bigger part
Now kinetic energy E=P2 (2 × 4m)
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