1 Laws of Motion
A body of mass 2 kg is hung on a spring balance mounted vertically in a lift. If the lift descends with an acceleration equal to the acceleration due to gravity ‘g’, the reading on the spring balance will be 1) 2 kg 2) (4 x g) kg 3) (2 x g) kg 4) Zero
SOLUTION: Reading on the spring balance = m (g – a) and since a = g ∴ Force = 0
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