1 Laws of Motion
In the following figure, calculate the value of force exerted on the 1.5 kg block by the 2.5 kg block.Given that all surfaces are frictionless.
1)25.0 N
2)28.2 N
3) 27.6 N
4)19.1 N
SOLUTION:
Force on 1.5 kg block due to 2.5 kg block=gravitational force on 2.5 g block along inclined plane force=mgsin50=2.5 ×10 × 0.766=19.15 N
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