Solution:
Solution :
At pressure P1 = 1 bar,
volume V1 = 2.27 L
At pressure P2 = 0.2 bar,
volume V2 = to be calculated
As temperature remain constant at room temperature, applying Boyle’s law
P1V1 = P2V2
(1 bar) (2.27 L) = (0.2 bar) V2
Thus, the balloon can be expanded upto 11.35 L. Beyond this volume it will burst.
