1 Probability
The probability that at least one of $$A$$ and $$B$$ occurs is $$0.6$$ and probability that they occur simultaneously is $$0.3$$, then $$P(A')+P(B')$$ is:
1) $$0.9$$ 2) $$1.15$$ 3) $$1.1$$ 4) $$1.2$$
We have have $$P(A\cup B)=0.6$$ and $$P(A\cap B)=0.3$$. We know that $$P(A)+P(B)=P(A\cup B)+(A\cap B)=0.6+0.3=0.9$$ $$\therefore P(A')+P(B')=1-P(B)+1-P(A)=2-0.9=1.1$$
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