Solution:
Solution
Students A and B have probabilities of failing an exam of $$\dfrac{1}{2}$$ and $$\dfrac{1}{5}$$ respectively. The probability of them both failing the examination is $$\dfrac{1}{10}$$
$$P(A∪B) = P(A) + P(B) - P(A∩B)=$$$$\dfrac{1}{2}$$$$+\dfrac{1}{5}$$$$-\dfrac{1}{10}$$$$=\dfrac{6}{10}=0.6$$
