1 Differentiation
If the functions f(x)=sin(x+a) and g(x)=bsinx+ccosx satisfy f(0)=g(0) and f′(0)=g′(0) then
1) b=π / 2? 2) b=cosa 3) c=sina 4) c=cosa
SOLUTION
Given, f(x)=sin(x+a)
and g(x)=bsinx+ccosx f(0)=g(0)⇒sina=c f′(x)=cos(x+a) g′(x)=bcosx−csinx f′(0)=g′(0)⇒cosa=b
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