Solution:
Solution
Mean $$= \mu = np $$ = 12; $$n =$$ number of trials ; $$p =$$ probability of success ; $$q = (1-p) =$$ probability of failure
Variance $$ ={ \sigma }^{ 2 } = npq = 8 $$
$$ 8 = np(1-p) = 12(1-p) $$ ;
$$ p = \dfrac {1 }{ 3 } $$
$$ \mu = np = 12$$
$$ n = \dfrac { 12}{ p } = 12 \times \dfrac { 3 }{ 1 } = 36 $$
Parameters are $$n =36$$ and $$ p = \dfrac {1 }{ 3 } $$
