1 Chemical Kinetics
If the half-life of an isotope X is 10 years, its decay constant is
1) 0.00692 Yr -1
2) 0.06932 Yr -1
3) 0.6932 Yr -1
4) 6.932 Yr -1
SOLUTION
$$\displaystyle{K}=\frac{{{0.693}}}{{{t}_{{{1}\text{/}{2}}}}},{K}=\frac{{{0.693}}}{{{10}}}=={0.0693}{y}{r}^{{-{1}}}$$
Your Score:
