Solution:
Solution
Eq. wt of Ferrous ammonium sulphate=392
Normality of salt solution=(3.92/392)(1000/100)=0.1N
20 ml of 0.1N salt sol.=18ml of KMnO4 sol
Thus from N1V1=N2V2
Normality of KMnO4; N2=(1/9) N
As eq.wt of KMnO4=31.6
∴ strength of KMnO4 sol=(1/9) 31.6=3.5 g/l approx
